A Cube Of Iron { \left(C_p=0.450 , \text{J/g} \cdot{ }^{\circ} \text{C} \right)$}$ With A Mass Of 55.8 G Is Heated From ${ 25.0^{\circ} \text{C}\$} To ${ 49.0^{\circ} \text{C}\$} . How Much Heat Is Required For This Process?
Introduction
In this article, we will explore the concept of heat transfer and how it applies to a cube of iron. We will calculate the amount of heat required to heat a cube of iron from an initial temperature to a final temperature. This problem is relevant to the field of chemistry, specifically thermodynamics, and will help us understand the principles of heat transfer.
The Problem
We are given a cube of iron with a mass of 55.8 g and a specific heat capacity of 0.450 J/g°C. The cube is initially at a temperature of 25.0°C and is heated to a final temperature of 49.0°C. We need to calculate the amount of heat required for this process.
The Formula
The formula to calculate the heat required for a process is:
Q = mcΔT
Where:
- Q is the heat required (in Joules)
- m is the mass of the object (in grams)
- c is the specific heat capacity (in J/g°C)
- ΔT is the change in temperature (in °C)
Calculating the Change in Temperature
The change in temperature (ΔT) is the difference between the final temperature and the initial temperature.
ΔT = T_f - T_i = 49.0°C - 25.0°C = 24.0°C
Calculating the Heat Required
Now that we have the change in temperature, we can plug in the values into the formula to calculate the heat required.
Q = mcΔT = (55.8 g) × (0.450 J/g°C) × (24.0°C) = 572.16 J
Conclusion
In this article, we calculated the amount of heat required to heat a cube of iron from an initial temperature to a final temperature. We used the formula Q = mcΔT and plugged in the values to get the answer. This problem is relevant to the field of chemistry, specifically thermodynamics, and helps us understand the principles of heat transfer.
Discussion
This problem is a simple example of heat transfer, but it has many real-world applications. For example, in a car engine, heat is transferred from the engine block to the radiator to cool the engine. In a refrigerator, heat is transferred from the cold interior to the hot exterior to cool the contents. Understanding the principles of heat transfer is crucial in designing and building these systems.
Real-World Applications
Heat transfer is a critical concept in many real-world applications, including:
- Engine design: Heat transfer is crucial in designing car engines, where heat is transferred from the engine block to the radiator to cool the engine.
- Refrigeration: Heat transfer is used in refrigerators to cool the contents by transferring heat from the cold interior to the hot exterior.
- Building design: Heat transfer is used in building design to ensure that buildings are energy-efficient and comfortable to live in.
- Medical applications: Heat transfer is used in medical applications, such as hyperthermia treatment, where heat is applied to the body to kill cancer cells.
Conclusion
Introduction
In our previous article, we calculated the amount of heat required to heat a cube of iron from an initial temperature to a final temperature. In this article, we will answer some frequently asked questions related to the problem.
Q: What is the specific heat capacity of iron?
A: The specific heat capacity of iron is 0.450 J/g°C.
Q: What is the mass of the cube of iron?
A: The mass of the cube of iron is 55.8 g.
Q: What is the initial temperature of the cube of iron?
A: The initial temperature of the cube of iron is 25.0°C.
Q: What is the final temperature of the cube of iron?
A: The final temperature of the cube of iron is 49.0°C.
Q: How do I calculate the heat required for a process?
A: To calculate the heat required for a process, you can use the formula Q = mcΔT, where Q is the heat required, m is the mass of the object, c is the specific heat capacity, and ΔT is the change in temperature.
Q: What is the change in temperature (ΔT)?
A: The change in temperature (ΔT) is the difference between the final temperature and the initial temperature. In this case, ΔT = 49.0°C - 25.0°C = 24.0°C.
Q: How do I calculate the heat required using the formula Q = mcΔT?
A: To calculate the heat required using the formula Q = mcΔT, you can plug in the values as follows:
Q = (55.8 g) × (0.450 J/g°C) × (24.0°C) = 572.16 J
Q: What is the significance of heat transfer in real-world applications?
A: Heat transfer is a critical concept in many real-world applications, including engine design, refrigeration, building design, and medical applications. Understanding the principles of heat transfer is crucial in designing and building these systems.
Q: Can you give some examples of heat transfer in real-world applications?
A: Yes, here are some examples of heat transfer in real-world applications:
- Engine design: Heat transfer is crucial in designing car engines, where heat is transferred from the engine block to the radiator to cool the engine.
- Refrigeration: Heat transfer is used in refrigerators to cool the contents by transferring heat from the cold interior to the hot exterior.
- Building design: Heat transfer is used in building design to ensure that buildings are energy-efficient and comfortable to live in.
- Medical applications: Heat transfer is used in medical applications, such as hyperthermia treatment, where heat is applied to the body to kill cancer cells.
Conclusion
In conclusion, this article answers some frequently asked questions related to the problem of calculating the amount of heat required to heat a cube of iron from an initial temperature to a final temperature. We hope that this article has provided you with a better understanding of the principles of heat transfer and its significance in real-world applications.