A Chemistry Teacher Adds 50.0 ML Of $1.50 , \text{M} , H_2SO_4$ Solution To 200 ML Of Water. What Is The Concentration Of The Final Solution?Use $M_i V_i = M_t V_t$.A. 0.300 M B. 0.375 M C. 6.00 M D. 750 M

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Understanding the Problem

To find the concentration of the final solution, we need to use the concept of dilution. When a solution is diluted by adding more solvent, the concentration of the solute decreases. In this case, we are adding 50.0 mL of $1.50 , \text{M} , H_2SO_4$ solution to 200 mL of water. We need to find the concentration of the final solution.

Using the Dilution Formula

The dilution formula is given by:

MiVi=MtVtM_i V_i = M_t V_t

where:

  • M_i$ is the initial concentration of the solution

  • V_i$ is the initial volume of the solution

  • M_t$ is the final concentration of the solution

  • V_t$ is the final volume of the solution

Calculating the Final Concentration

We are given:

  • Mi=1.50 MM_i = 1.50 \, \text{M}

  • Vi=50.0 mLV_i = 50.0 \, \text{mL}

  • Vt=200 mLV_t = 200 \, \text{mL}

We need to find $M_t$.

Converting the Volumes to the Same Units

We need to convert the volumes to the same units. Let's convert the initial volume from mL to L:

Vi=50.0 mL=0.0500 LV_i = 50.0 \, \text{mL} = 0.0500 \, \text{L}

Plugging in the Values

Now we can plug in the values into the dilution formula:

MiVi=MtVtM_i V_i = M_t V_t

1.50 M×0.0500 L=Mt×0.200 L1.50 \, \text{M} \times 0.0500 \, \text{L} = M_t \times 0.200 \, \text{L}

Solving for $M_t$

Now we can solve for $M_t$:

Mt=1.50 M×0.0500 L0.200 LM_t = \frac{1.50 \, \text{M} \times 0.0500 \, \text{L}}{0.200 \, \text{L}}

Mt=0.0750 M L0.200 LM_t = \frac{0.0750 \, \text{M} \, \text{L}}{0.200 \, \text{L}}

Mt=0.375 MM_t = 0.375 \, \text{M}

Conclusion

The concentration of the final solution is $0.375 , \text{M}$.

Answer

The correct answer is B. 0.375 M.

Discussion

This problem is a classic example of dilution. When a solution is diluted by adding more solvent, the concentration of the solute decreases. In this case, we added 50.0 mL of $1.50 , \text{M} , H_2SO_4$ solution to 200 mL of water, resulting in a final concentration of $0.375 , \text{M}$.

Importance of Dilution

Dilution is an important concept in chemistry. It is used to reduce the concentration of a solution, making it safer to handle. It is also used to prepare solutions of a specific concentration for laboratory experiments.

Real-World Applications

Dilution has many real-world applications. For example, in medicine, dilution is used to prepare solutions of a specific concentration for patients. In industry, dilution is used to prepare solutions of a specific concentration for manufacturing processes.

Conclusion

In conclusion, the concentration of the final solution is $0.375 , \text{M}$. This problem is a classic example of dilution, and it highlights the importance of understanding this concept in chemistry.

Understanding the Problem

To find the concentration of the final solution, we need to use the concept of dilution. When a solution is diluted by adding more solvent, the concentration of the solute decreases. In this case, we are adding 50.0 mL of $1.50 , \text{M} , H_2SO_4$ solution to 200 mL of water. We need to find the concentration of the final solution.

Using the Dilution Formula

The dilution formula is given by:

MiVi=MtVtM_i V_i = M_t V_t

where:

  • M_i$ is the initial concentration of the solution

  • V_i$ is the initial volume of the solution

  • M_t$ is the final concentration of the solution

  • V_t$ is the final volume of the solution

Calculating the Final Concentration

We are given:

  • Mi=1.50 MM_i = 1.50 \, \text{M}

  • Vi=50.0 mLV_i = 50.0 \, \text{mL}

  • Vt=200 mLV_t = 200 \, \text{mL}

We need to find $M_t$.

Converting the Volumes to the Same Units

We need to convert the volumes to the same units. Let's convert the initial volume from mL to L:

Vi=50.0 mL=0.0500 LV_i = 50.0 \, \text{mL} = 0.0500 \, \text{L}

Plugging in the Values

Now we can plug in the values into the dilution formula:

MiVi=MtVtM_i V_i = M_t V_t

1.50 M×0.0500 L=Mt×0.200 L1.50 \, \text{M} \times 0.0500 \, \text{L} = M_t \times 0.200 \, \text{L}

Solving for $M_t$

Now we can solve for $M_t$:

Mt=1.50 M×0.0500 L0.200 LM_t = \frac{1.50 \, \text{M} \times 0.0500 \, \text{L}}{0.200 \, \text{L}}

Mt=0.0750 M L0.200 LM_t = \frac{0.0750 \, \text{M} \, \text{L}}{0.200 \, \text{L}}

Mt=0.375 MM_t = 0.375 \, \text{M}

Conclusion

The concentration of the final solution is $0.375 , \text{M}$.

Answer

The correct answer is B. 0.375 M.

Discussion

This problem is a classic example of dilution. When a solution is diluted by adding more solvent, the concentration of the solute decreases. In this case, we added 50.0 mL of $1.50 , \text{M} , H_2SO_4$ solution to 200 mL of water, resulting in a final concentration of $0.375 , \text{M}$.

Importance of Dilution

Dilution is an important concept in chemistry. It is used to reduce the concentration of a solution, making it safer to handle. It is also used to prepare solutions of a specific concentration for laboratory experiments.

Real-World Applications

Dilution has many real-world applications. For example, in medicine, dilution is used to prepare solutions of a specific concentration for patients. In industry, dilution is used to prepare solutions of a specific concentration for manufacturing processes.

Conclusion

In conclusion, the concentration of the final solution is $0.375 , \text{M}$. This problem is a classic example of dilution, and it highlights the importance of understanding this concept in chemistry.

Q&A

Q: What is dilution?

A: Dilution is the process of adding more solvent to a solution, resulting in a decrease in the concentration of the solute.

Q: What is the formula for dilution?

A: The formula for dilution is given by:

MiVi=MtVtM_i V_i = M_t V_t

where:

  • M_i$ is the initial concentration of the solution

  • V_i$ is the initial volume of the solution

  • M_t$ is the final concentration of the solution

  • V_t$ is the final volume of the solution

Q: How do I calculate the final concentration of a solution after dilution?

A: To calculate the final concentration of a solution after dilution, you need to use the dilution formula. Plug in the values of the initial concentration, initial volume, and final volume, and solve for the final concentration.

Q: What is the importance of dilution in chemistry?

A: Dilution is an important concept in chemistry because it is used to reduce the concentration of a solution, making it safer to handle. It is also used to prepare solutions of a specific concentration for laboratory experiments.

Q: What are some real-world applications of dilution?

A: Dilution has many real-world applications, including medicine and industry. In medicine, dilution is used to prepare solutions of a specific concentration for patients. In industry, dilution is used to prepare solutions of a specific concentration for manufacturing processes.

Q: How do I convert the volumes of a solution from mL to L?

A: To convert the volumes of a solution from mL to L, you need to divide the volume in mL by 1000.

Q: What is the final concentration of a solution after adding 50.0 mL of $1.50 , \text{M} , H_2SO_4$ solution to 200 mL of water?

A: The final concentration of the solution is $0.375 , \text{M}$.

Conclusion

In conclusion, dilution is an important concept in chemistry that is used to reduce the concentration of a solution, making it safer to handle. It is also used to prepare solutions of a specific concentration for laboratory experiments. The formula for dilution is given by:

MiVi=MtVtM_i V_i = M_t V_t

where:

  • M_i$ is the initial concentration of the solution

  • V_i$ is the initial volume of the solution

  • M_t$ is the final concentration of the solution

  • V_t$ is the final volume of the solution

We hope this article has helped you understand the concept of dilution and how to calculate the final concentration of a solution after dilution.