A Box Is Pushed Down At An Angle Of 32 Degrees On A Rough Surface. The Box Moves To The Right.What Equation Should Be Used To Find The Net Force In The $y$-direction?A. $F_{\text{net}, Y} = F_N - F_g$B. $F_{\text{net},

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Introduction

When a box is pushed down an angle on a rough surface, it experiences various forces acting upon it. The primary forces involved are the normal force (F_N) exerted by the surface, the force of gravity (F_g) acting downward, and the net force (F_net) resulting from the combination of these forces. In this scenario, the box moves to the right, indicating that the net force in the x-direction is not zero. However, we are interested in finding the net force in the y-direction, which requires a careful analysis of the forces acting on the box.

Forces Acting on the Box

The box is subject to the following forces:

  • Normal Force (F_N): The normal force is the force exerted by the surface on the box, perpendicular to the surface. Since the box is pushed down an angle, the normal force will be directed upward, opposing the force of gravity.
  • Force of Gravity (F_g): The force of gravity acts downward, pulling the box toward the ground.
  • Net Force (F_net): The net force is the vector sum of all forces acting on the box. In this case, we are interested in finding the net force in the y-direction.

Finding the Net Force in the Y-Direction

To find the net force in the y-direction, we need to consider the forces acting on the box in the y-direction. The normal force (F_N) and the force of gravity (F_g) are the primary forces acting in the y-direction. Since the box is moving to the right, the net force in the x-direction is not zero, but it does not affect the net force in the y-direction.

The correct equation to find the net force in the y-direction is:

Fnet,y=FN−FgF_{\text{net}, y} = F_N - F_g

This equation represents the difference between the normal force (F_N) and the force of gravity (F_g) acting on the box in the y-direction.

Analysis of the Equation

Let's analyze the equation:

Fnet,y=FN−FgF_{\text{net}, y} = F_N - F_g

  • F_N: The normal force (F_N) is directed upward, opposing the force of gravity. Since the box is pushed down an angle, the normal force will be less than the force of gravity.
  • F_g: The force of gravity (F_g) acts downward, pulling the box toward the ground.
  • F_net,y: The net force in the y-direction (F_net,y) is the difference between the normal force (F_N) and the force of gravity (F_g).

Conclusion

In conclusion, when a box is pushed down an angle on a rough surface and moves to the right, the correct equation to find the net force in the y-direction is:

Fnet,y=FN−FgF_{\text{net}, y} = F_N - F_g

This equation represents the difference between the normal force (F_N) and the force of gravity (F_g) acting on the box in the y-direction. By analyzing the forces acting on the box, we can determine the net force in the y-direction, which is essential for understanding the motion of the box.

Example Problem

Suppose a box is pushed down an angle of 32 degrees on a rough surface, and it moves to the right. The normal force (F_N) is 50 N, and the force of gravity (F_g) is 100 N. Find the net force in the y-direction.

Using the equation:

Fnet,y=FN−FgF_{\text{net}, y} = F_N - F_g

We can substitute the values:

Fnet,y=50 N−100 N=−50 NF_{\text{net}, y} = 50\, \text{N} - 100\, \text{N} = -50\, \text{N}

The negative sign indicates that the net force in the y-direction is downward.

Final Thoughts

In this article, we discussed the forces acting on a box pushed down an angle on a rough surface and moved to the right. We analyzed the forces in the y-direction and derived the correct equation to find the net force in the y-direction. By understanding the forces acting on the box, we can determine the net force in the y-direction, which is essential for understanding the motion of the box.

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Introduction

In our previous article, we discussed the forces acting on a box pushed down an angle on a rough surface and moved to the right. We analyzed the forces in the y-direction and derived the correct equation to find the net force in the y-direction. In this article, we will answer some frequently asked questions related to this topic.

Q&A

Q1: What is the normal force (F_N) in the scenario?

A1: The normal force (F_N) is the force exerted by the surface on the box, perpendicular to the surface. In this scenario, the normal force is directed upward, opposing the force of gravity.

Q2: What is the force of gravity (F_g) in the scenario?

A2: The force of gravity (F_g) is the force acting downward, pulling the box toward the ground. In this scenario, the force of gravity is 100 N.

Q3: What is the net force in the y-direction (F_net,y)?

A3: The net force in the y-direction (F_net,y) is the difference between the normal force (F_N) and the force of gravity (F_g). In this scenario, the net force in the y-direction is:

Fnet,y=FN−FgF_{\text{net}, y} = F_N - F_g

Q4: What is the effect of the net force in the y-direction on the box?

A4: The net force in the y-direction affects the motion of the box in the y-direction. If the net force in the y-direction is upward, the box will accelerate upward. If the net force in the y-direction is downward, the box will accelerate downward.

Q5: How does the angle of the push affect the forces acting on the box?

A5: The angle of the push affects the normal force (F_N) and the force of gravity (F_g). As the angle of the push increases, the normal force (F_N) decreases, and the force of gravity (F_g) remains constant.

Q6: What is the relationship between the net force in the y-direction and the motion of the box?

A6: The net force in the y-direction is directly related to the motion of the box in the y-direction. If the net force in the y-direction is zero, the box will not accelerate in the y-direction. If the net force in the y-direction is non-zero, the box will accelerate in the y-direction.

Example Problems

Problem 1:

A box is pushed down an angle of 32 degrees on a rough surface, and it moves to the right. The normal force (F_N) is 50 N, and the force of gravity (F_g) is 100 N. Find the net force in the y-direction.

Solution:

Using the equation:

Fnet,y=FN−FgF_{\text{net}, y} = F_N - F_g

We can substitute the values:

Fnet,y=50 N−100 N=−50 NF_{\text{net}, y} = 50\, \text{N} - 100\, \text{N} = -50\, \text{N}

The negative sign indicates that the net force in the y-direction is downward.

Problem 2:

A box is pushed down an angle of 45 degrees on a rough surface, and it moves to the right. The normal force (F_N) is 75 N, and the force of gravity (F_g) is 100 N. Find the net force in the y-direction.

Solution:

Using the equation:

Fnet,y=FN−FgF_{\text{net}, y} = F_N - F_g

We can substitute the values:

Fnet,y=75 N−100 N=−25 NF_{\text{net}, y} = 75\, \text{N} - 100\, \text{N} = -25\, \text{N}

The negative sign indicates that the net force in the y-direction is downward.

Final Thoughts

In this article, we answered some frequently asked questions related to the forces acting on a box pushed down an angle on a rough surface and moved to the right. We analyzed the forces in the y-direction and derived the correct equation to find the net force in the y-direction. By understanding the forces acting on the box, we can determine the net force in the y-direction, which is essential for understanding the motion of the box.