A Bag Contains 2 Bananas, 3 Apples, And 5 Pears. Find The Following Probabilities And Express Your Answer As A Fraction And As A Percentage:2.1 P(banana Is Chosen)2.2 P(pear Is Chosen)2.3 P(banana Or Apple Is Chosen)2.4 P(no Apples Are Chosen)

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Introduction

In this article, we will explore the concept of probability and how it can be applied to real-world scenarios. We will use a bag containing 2 bananas, 3 apples, and 5 pears to calculate various probabilities. Probability is a measure of the likelihood of an event occurring, and it is often expressed as a fraction or a percentage.

Calculating Probabilities

2.1 P(banana is chosen)

To calculate the probability of choosing a banana, we need to divide the number of bananas by the total number of fruits in the bag.

Number of bananas: 2 Total number of fruits: 2 + 3 + 5 = 10

P(banana is chosen) = Number of bananas / Total number of fruits = 2/10 = 1/5 = 0.2

As a percentage, the probability of choosing a banana is:

P(banana is chosen) = 0.2 x 100% = 20%

2.2 P(pear is chosen)

To calculate the probability of choosing a pear, we need to divide the number of pears by the total number of fruits in the bag.

Number of pears: 5 Total number of fruits: 2 + 3 + 5 = 10

P(pear is chosen) = Number of pears / Total number of fruits = 5/10 = 1/2 = 0.5

As a percentage, the probability of choosing a pear is:

P(pear is chosen) = 0.5 x 100% = 50%

2.3 P(banana or apple is chosen)

To calculate the probability of choosing a banana or an apple, we need to add the number of bananas and apples and divide by the total number of fruits in the bag.

Number of bananas: 2 Number of apples: 3 Total number of fruits: 2 + 3 + 5 = 10

P(banana or apple is chosen) = (Number of bananas + Number of apples) / Total number of fruits = (2 + 3) / 10 = 5/10 = 1/2 = 0.5

As a percentage, the probability of choosing a banana or an apple is:

P(banana or apple is chosen) = 0.5 x 100% = 50%

2.4 P(no apples are chosen)

To calculate the probability of not choosing an apple, we need to divide the number of fruits that are not apples by the total number of fruits in the bag.

Number of fruits that are not apples: 2 + 5 = 7 Total number of fruits: 2 + 3 + 5 = 10

P(no apples are chosen) = Number of fruits that are not apples / Total number of fruits = 7/10 = 0.7

As a percentage, the probability of not choosing an apple is:

P(no apples are chosen) = 0.7 x 100% = 70%

Conclusion

Introduction

In our previous article, we explored the concept of probability and calculated various probabilities using a bag containing 2 bananas, 3 apples, and 5 pears. In this article, we will answer some frequently asked questions related to probability and provide additional insights into the world of probability.

Q&A

Q: What is the probability of choosing a fruit that is not a banana?

A: To calculate the probability of choosing a fruit that is not a banana, we need to divide the number of fruits that are not bananas by the total number of fruits in the bag.

Number of fruits that are not bananas: 3 + 5 = 8 Total number of fruits: 2 + 3 + 5 = 10

P(fruit is not a banana) = Number of fruits that are not bananas / Total number of fruits = 8/10 = 0.8

As a percentage, the probability of choosing a fruit that is not a banana is:

P(fruit is not a banana) = 0.8 x 100% = 80%

Q: What is the probability of choosing a fruit that is not a pear?

A: To calculate the probability of choosing a fruit that is not a pear, we need to divide the number of fruits that are not pears by the total number of fruits in the bag.

Number of fruits that are not pears: 2 + 3 = 5 Total number of fruits: 2 + 3 + 5 = 10

P(fruit is not a pear) = Number of fruits that are not pears / Total number of fruits = 5/10 = 0.5

As a percentage, the probability of choosing a fruit that is not a pear is:

P(fruit is not a pear) = 0.5 x 100% = 50%

Q: What is the probability of choosing a fruit that is both a banana and an apple?

A: Since there are no fruits that are both bananas and apples, the probability of choosing a fruit that is both a banana and an apple is 0.

P(fruit is both a banana and an apple) = 0

Q: What is the probability of choosing a fruit that is either a banana or a pear?

A: To calculate the probability of choosing a fruit that is either a banana or a pear, we need to add the number of bananas and pears and divide by the total number of fruits in the bag.

Number of bananas: 2 Number of pears: 5 Total number of fruits: 2 + 3 + 5 = 10

P(fruit is either a banana or a pear) = (Number of bananas + Number of pears) / Total number of fruits = (2 + 5) / 10 = 7/10 = 0.7

As a percentage, the probability of choosing a fruit that is either a banana or a pear is:

P(fruit is either a banana or a pear) = 0.7 x 100% = 70%

Q: What is the probability of choosing a fruit that is neither a banana nor a pear?

A: To calculate the probability of choosing a fruit that is neither a banana nor a pear, we need to divide the number of fruits that are neither bananas nor pears by the total number of fruits in the bag.

Number of fruits that are neither bananas nor pears: 3 Total number of fruits: 2 + 3 + 5 = 10

P(fruit is neither a banana nor a pear) = Number of fruits that are neither bananas nor pears / Total number of fruits = 3/10 = 0.3

As a percentage, the probability of choosing a fruit that is neither a banana nor a pear is:

P(fruit is neither a banana nor a pear) = 0.3 x 100% = 30%

Conclusion

In this article, we answered some frequently asked questions related to probability and provided additional insights into the world of probability. We calculated various probabilities using a bag containing 2 bananas, 3 apples, and 5 pears, and demonstrated the importance of probability in real-world scenarios.